 # Vedic Maths Tutorial

## text-picture version

Vedic Maths is based on sixteen sutras or principles. These principles are general in nature and can be applied in many ways. In practice many applications of the sutras may be learned and combined to solve actual problems. These tutorials will give examples of simple applications of the sutras, to give a feel for how the Vedic Maths system works. These tutorials do not attempt to teach the systematic use of the sutras. For more advanced applications and a more complete coverage of the basic uses of the sutras, we recommend you study one of the texts available.

N.B. The following tutorials are based on examples and exercises given in the book 'Fun with figures' by Kenneth Williams, which is a fun introduction some of the applications of the sutras for children.

# Tutorial 1

Use the formula ALL FROM 9 AND THE LAST FROM 10 to perform instant subtractions.

• For example 1000 - 357 = 643

We simply take each figure in 357 from 9 and the last figure from 10. So the answer is 1000 - 357 = 643

And thats all there is to it!

This always works for subtractions from numbers consisting of a 1 followed by noughts: 100; 1000; 10,000 etc.

• Similarly 10,000 - 1049 = 8951 • For 1000 - 83, in which we have more zeros than figures in the numbers being subtracted, we simply suppose 83 is 083.

So 1000 - 83 becomes 1000 - 083 = 917

Try some yourself:

1) 1000 - 777
2) 1000 - 283
3) 1000 - 505
4) 10,000 - 2345
5) 10000 - 9876
6) 10,000 - 1101
7) 100 - 57
8) 1000 - 57
9) 10,000 - 321
10) 10,000 - 38

# Tutorial 2

Using VERTICALLY AND CROSSWISE you do not need to the multiplication tables beyond 5 X 5.

• Suppose you need 8 x 7

8 is 2 below 10 and 7 is 3 below 10.
Think of it like this: The diagram below shows how you get it. You subtract crosswise 8-3 or 7 - 2 to get 5,
the first figure of the answer.
And you multiply vertically: 2 x 3 to get 6,
the last figure of the answer.

That's all you do:

See how far the numbers are below 10, subtract one
number's deficiency from the other number, and
multiply the deficiencies together.

• 7 x 6 = 42 Here there is a carry: the 1 in the 12 goes over to make 3 into 4.

Multiply these: Here's how to use VERTICALLY AND CROSSWISE for multiplying numbers close to 100.

• Suppose you want to multiply 88 by 98.

Not easy,you might think. But with
VERTICALLY AND CROSSWISE you can give
the answer immediately, using the same method
as on the page.

Both 88 and 98 are close to 100.
88 is 12 below 100 and 98 is 2 below 100.

You can imagine the sum set out like this: As before the 86 comes from
subtracting crosswise: 88 - 2 = 86
(or 98 - 12 = 86: you can subtract
either way, you will always get
And the 24 in the answer is
just 12 x 2: you multiply vertically.
So 88 x 98 = 8624

This is so easy it is just mental arithmetic.

Try some: Multiplying numbers just over 100.

• 103 x 104 = 10712

The answer is in two parts: 107 and 12,
107 is just 103 + 4 (or 104 + 3),
and 12 is just 3 x 4.

• Similarly 107 x 106 = 11342

107 + 6 = 113 and 7 x 6 = 42

Again, just for mental arithmetic

Try a few:

1) 102 x 107
2) 106 x 103
3) 104 x 104
4) 109 x 108
5) 101 x123
6) 103 x102

# Tutorial 3

The easy way to add and subtract fractions.

Use VERTICALLY AND CROSSWISE to write the answer straight down!

• • Multiply crosswise and add to get the top of the answer:
2 x 5 = 10 and 1 x 3 = 3. Then 10 + 3 = 13.
The bottom of the fraction is just 3 x 5 = 15.
You multiply the bottom number together.

So:
• Subtracting is just as easy: multiply crosswise as before, but the subtract:

• Try a few: # Tutorial 4

A quick way to square numbers that end in 5 using the formula BY ONE MORE THAN THE ONE BEFORE.

• 752 = 5625

752 means 75 x 75.
The answer is in two parts: 56 and 25.
The last part is always 25.
The first part is the first number, 7, multiplied by the number "one more", which is 8:
so 7 x 8 = 56 • Similarly 852 = 7225 because 8 x 9 = 72.

Try these:

1) 452 2) 652 3) 952 4) 352 5) 152

Method for multiplying numbers where the first figures are the same and the last figures add up to 10.

• 32 x 38 = 1216
figures (2 and 8) add up to 10.

So we just multiply 3 by 4 (the next number up)
to get 12 for the first part of the answer.

And we multiply the last figures: 2 x 8 = 16 to
get the last part of the answer.

Diagrammatically: • And 81 x 89 = 7209
• We put 09 since we need two figures as in all the other examples.

Practise some:

1) 43 x 47
2) 24 x 26
3) 62 x 68
4) 17 x 13
5) 59 x 51
6) 77 x 73

# Tutorial 5

An elegant way of multiplying numbers using a simple pattern.

• 21 x 23 = 483
• This is normally called long multiplication but
actually the answer can be written straight down
using the VERTICALLY AND CROSSWISE
formula.

We first put, or imagine, 23 below 21: There are 3 steps:

a) Multiply vertically on the left: 2 x 2 = 4.
This gives the first figure of the answer.
b) Multiply crosswise and add: 2 x 3 + 1 x 2 = 8
This gives the middle figure.
c) Multiply vertically on the right: 1 x 3 = 3
This gives the last figure of the answer.

And thats all there is to it.

• Similarly 61 x 31 = 1891
• • 6 x 3 = 18; 6 x 1 + 1 x 3 = 9; 1 x 1 = 1

Try these, just write down the answer: Multiply any 2-figure numbers together by mere mental arithmetic!

If you want 21 stamps at 26 pence each you can

There were no carries in the method given above.
However, there only involve one small extra step.

• 21 x 26 = 546 The method is the same as above
except that we get a 2-figure number, 14, in the
middle step, so the 1 is carried over to the left
(4 becomes 5).

So 21 stamps cost £5.46.

Practise a few: • 33 x 44 = 1452
• There may be more than one carry in a sum: Vertically on the left we get 12.
Crosswise gives us 24, so we carry 2 to the left
and mentally get 144.

Then vertically on the right we get 12 and the 1
here is carried over to the 144 to make 1452. Any two numbers, no matter how big, can be
multiplied in one line by this method.

# Tutorial 6

Multiplying a number by 11.

To multiply any 2-figure number by 11 we just put
the total of the two figures between the 2 figures.

• 26 x 11 = 286

Notice that the outer figures in 286 are the 26
being multiplied.

And the middle figure is just 2 and 6 added up.

• So 72 x 11 = 792

Multiply by 11:

1) 43 2) 81 3) 15 4) 44 5) 11

• 77 x 11 = 847

This involves a carry figure because 7 + 7 = 14
we get 77 x 11 = 7147 = 847.

Multiply by 11:

1) 88 2) 84 3) 48 4) 73 5) 56

• 234 x 11 = 2574

We put the 2 and the 4 at the ends.
We add the first pair 2 + 3 = 5.
and we add the last pair: 3 + 4 = 7.

Multiply by 11:

1) 151 2) 527 3) 333 4) 714 5) 909

# Tutorial 7

Method for diving by 9.

• 23 / 9 = 2 remainder 5

The first figure of 23 is 2, and this is the answer.
The remainder is just 2 and 3 added up!

• 43 / 9 = 4 remainder 7

The first figure 4 is the answer
and 4 + 3 = 7 is the remainder - could it be easier?

Divide by 9:

1) 61 2) 33 3) 44 4) 53 5) 80

• 134 / 9 = 14 remainder 8

The answer consists of 1,4 and 8.
1 is just the first figure of 134.
4 is the total of the first two figures 1+ 3 = 4,
and 8 is the total of all three figures 1+ 3 + 4 = 8.

Divide by 9:

6) 232 7) 151 8) 303 9) 212 10) 2121

• 842 / 9 = 812 remainder 14 = 92 remainder 14

Actually a remainder of 9 or more is not usually
permitted because we are trying to find how
many 9's there are in 842.

Since the remainder, 14 has one more 9 with 5
left over the final answer will be 93 remainder 5

Divide these by 9:

1) 771 2) 942 3) 565 4) 555 5) 777 6) 2382 7) 7070